Dear all,
My next question is about the EM-Sources.
(Don’t worry, the antenna issue has not been forgotten, but it still needs some time.)
- My professor and I are interested in what happens if the voltage source is meshed with more than one cell at the corner between the ‘pos’ and ‘neg’ cells.
To my knowledge, the excitation has to be very precise meshed, because in this region the highest amount of field changing is there. In the online tutorial for the patch antenna, excited by a coax cable with the voltage source/gap as excitation, the voltage source has the same size as the coax pin and is so several times bigger than lambda. Also the mesh.
So what happens at NSEM if the source is meshed by more than two cells in total?
By trying it out I got some results (see picture), but how correct are there? For S11 and Z_in it doesn’t look realistic. The rest is similar to the original meshing interval.
**JOU**
reset
reset aprepro
Parameter, all definitions in mil
#{sub_h=31}
#{sub_w=787}
#{patch_w = 187}
#{coax_l = 100}
#{coax_r = 20}
#{pin_r = 6}
#{vs_w = 2*pin_r}
#{pin_l = sub_h+coax_l-vs_w}
#{feed_offset = 0.68}
#{mesh_size = (0.3/171000/25.41000)/10}
#{freq = 16e9}
#{co = 3e8}
#{lambda = co/freq}
brick x {sub_h} y {sub_w} z {sub_w}
volume 1 rename “substrate”
move Volume substrate x {-sub_h/2} include_merged
create surface rectangle width {patch_w} xplane
volume 2 rename “patch_vol”
create surface rectangle width {sub_w} xplane
volume 3 rename “gnd”
move Surface in volume gnd x {-sub_h} include_merged
create Prism height {pin_l} sides 6 radius {pin_r}
volume 4 rename “pin”
rotate Volume 4 angle 90 about Y include_merged
move Volume 4 x {-pin_l/2} z {-patch_w/2+feed_offset*patch_w/2} include_merged
create Prism height {coax_l} sides 6 radius {coax_r}
rotate Volume 5 angle 90 about Y include_merged
move Volume 5 x {-sub_h-coax_l/2} z {-patch_w/2+feed_offset*patch_w/2} include_merged
volume 5 rename “coax”
create surface rectangle width {vs_w} zplane
volume 6 rename “feed”
move Surface 25 x {-sub_h-coax_l+vs_w/2} z {-patch_w/2+feed_offset*patch_w/2} include_merged
split surface 25 direction curve 60
project surface 10 onto surface 18 imprint
subtract volume coax from volume gnd keep_tool
subtract volume pin from volume substrate keep_tool
subtract volume pin from volume coax keep_tool
subtract volume feed from volume coax keep_tool
imprint volume all
merge volume all
block 1 add surface all
nsem load material library “E:\Michael\Nullspace_workspace\Material\materials.h5”
nsem assign volume substrate material ‘RO3003’
nsem assign volume coax material ‘Teflon’
nsem assign volume patch_vol material ‘PEC’
nsem assign volume gnd material ‘PEC’
nsem assign volume pin material ‘PEC’
nsem assign Surface 19 20 21 22 23 24 28 49 52 material ‘PEC’
nsem voltage source ‘port1’ pos surface 27 neg surface 26 impedance 50
surface all scheme pave
curve 60 61 58 interval 4
curve 60 61 58 scheme equal
surface in volume feed size
mesh surface in volume feed
surface not is_meshed in volume coax size {coax_r/2}
mesh surface not is_meshed in volume coax
surface in volume patch_vol size {mesh_size/3}
mesh surface in volume patch_vol
surface not is_meshed size {mesh_size}
mesh surface not is_meshed
nsem print status
**short Log file/ sim overview**
system : DENSE
fill tolerance : 0.0001
solve tolerance : 0.0001
element type = QUAD_4
gqCache beg
sizeof(P) (Bytes) : 8.0e+00
sizeof(Vector3<P>) (Bytes) : 2.4e+01
sizeof(Jacobian<P>) (Bytes) : 5.6e+01
gqCache (GB) : 9.9e-03
Nn : 797
Nb : 2968
Ne : 809
Nsb : 10
Ned : 1604
Nbe : 4
Nrhs : 1
process memory (GB) : -9.536743e-07 : -9.536743e-07
Sim time: 5.25min
10_GHz
RAM: GB
- The plane wave excitation: To define the incidence angle of the plane wave in response to the origin I choose theta (t) and phi (p). So far so clear, but how I can determine the polarisation of the incoming plane wave?
I understand that for the result I can choose the observation angle and get the different polarisation pp, pt, tp, tt. And that the excitation is automatically computes two linear polarisations, shifted by 90 °.
So for example for a plane wave by t = 90° and p= 0° the polarisations are co and cross-polarised (or linear polarisation in horizontal (co) and vertical (cross) polarisation). But also for that, how do I know concerning Paraview results which polarization is which regarding the given theta and phi angle?
In Para view the sheds called 0_0_Jp_Abs for positive current density and 0_1_Abs for negative current density. (0_2_, 0_3_,…,0_10_,0_11_, depends on the amount of excitation position).
For some significant points and well-known geometries like a sphere, you can try to imagine how the polarization is by take a view of the surface current, but not for more complex chosen incidence angles and geometries. Or I’m wrong and it’s an easy thing but only my knowledge is not high enough, so please, could you explain how I get the polarization by looking at the results?
I add an example from Parawiev with the chosen angle of incidence of the plane wave.
**surface current @ Paraview**
Incidence angle choosing by theta = 45° and phi = 90°
positive current density
Camera view @ Paraview Adjust Camera - Camera Paremeters - 0, 0.707, 0.707
positive current density by choose the second polarisation
( angle in respect to the origin unknown)
Camera view @ Paraview Adjust Camera - Camera Paremeters - 0, 0.707, 0.707
first plot by alignment of the coordinate axes x,y,z
**JOU**
reset
reset aprepro
#{f =10e9}
#{c=3e8}
#{lambda=c/f}
#{r=4*lambda}
create sphere radius {r}
nsem assign volume 1 material ‘PEC’
imprint all
merge all
set duplicate block elements off
block 1 add surface all
block all element type quad9
surface 1 size {lambda/5}
mesh surface 1
**short Log file/ sim overview**
system : DENSE
fill tolerance : 0.0001
solve tolerance : 0.0001
element type = QUAD_9
gqCache beg
sizeof(P) (Bytes) : 8.0e+00
sizeof(Vector3<P>) (Bytes) : 2.4e+01
sizeof(Jacobian<P>) (Bytes) : 5.6e+01
gqCache (GB) : 1.5e-01
Nn : 22206
Nb : 44408
Ne : 5551
Nsb : 1
Ned : 11102
Nbe : 12
Nrhs : 2
process memory (GB) : -9.536743e-07 : -9.536743e-07
simulation time: 6.26 min
10_GHz
using peak RAM: 59.42293167114258 GB